Net radiative heat transfer between two grey surfaces: Q = ε·σ·A·(T₁⁴ − T₂⁴).
Formula
$$ Q = \varepsilon \cdot \sigma \cdot A \cdot (T_1^4 - T_2^4), \; \sigma = 5.67 \times 10^{-8} $$Symbol legend
| Symbol | Meaning | Unit | Source |
|---|---|---|---|
| $ε$ | Emissivity | - | material property |
| $σ$ | Stefan-Boltzmann constant | W/(m²·K⁴) | 5.67e-8 |
| $A$ | Surface area | m² | geometry |
| $T_1, T_2$ | Hot and cold surface temperatures | K | converted from °C |
| $Q$ | Radiative heat flow | kW | result |
Sources
- Incropera - Fundamentals of Heat and Mass Transfer.