Time to equalise an asymmetrically flooded tank pair through a cross-flooding duct - must be ≤ 10 min per MSC.245(83) / MSC.362(92).
Formula
$$ \dot V = C_d \cdot A \cdot \sqrt{2 g h}, \quad t = \frac{V}{\dot V} $$
Symbol legend
| Symbol | Meaning | Unit | Source |
|---|---|---|---|
| $V$ | Flood-volume to transfer | m³ | layout |
| $A$ | Duct cross-section | m² | arrangement |
| $h$ | Head differential | m | initial heel × tank geometry |
| $C_d$ | Discharge coefficient | - | duct design |
Sources
- IMO Res MSC.245(83) and MSC.362(92).