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Stoichiometric Air–Fuel Ratio

Theoretical AFR from elemental composition: AFR = (11.53·C + 34.34·(H − O/8) + 4.32·S) / 100, for mass fractions expressed in percent.

CombustionFuel
Stoichiometric AFR
13.58 -
Formula, assumptions, and limits

Ultimate analysis approach: C reacts with 32/12 × O₂ (= 2.67), H with 32/4 × O₂ (= 8), S with 32/32 × O₂ (= 1). Dividing by the oxygen mass fraction in air (0.232) gives AFR. HFO/VLSFO 14.0–14.5; MGO 14.6; LNG 17.2.

Symbol legend

SymbolMeaningUnitSource
Carbon mass %% m/multimate analysis
Hydrogen mass %% m/multimate analysis
Oxygen mass %% m/multimate analysis
Sulphur mass %% m/mISO 8754
Stoichiometric air-fuel ratiokg air / kg fuelresult